Find the area of the triangle whose vertices are (1,1) (-1,4) and (3,2).
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Answer:
Plot the points in a rough diagram and take them in order.Let the vertices be A(1,2),B( - 3,4) and C( - 5, - 6) Now the area of ABC is = 12 { ( x1y2 ...
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Step-by-step explanation:
theStep-by-step explanation:
Answer:
Line JK passes through points J(-4,-5) and K(-6, 3).
Line JK has form of y = mx + b
=> -5 = -4m + b
=> 3 = -6m + b
Subtract 2nd equation from 1st equation:
=> -8 = 2m
=> m = -4
Substitute back m = -4 into 1st equation:
=> -5 = -4(-4) + b
=> b = -21
Hope this helps!
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