Find the area of the triangle whose vertices are (1, 2), (3, 7) and (5, 3)
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Answers
Answered by
0
Step-by-step explanation:
Area of triangle=
2
1
∣(x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
))∣ where x=1,x
2
=3,x
3
=5, y
1
=2,y
2
=7,y
3
=3
⇒
2
1
∣(1(7−3)+3(3−2)+5(2−7))∣
⇒
2
1
∣(1−(4)+3(1)+5(−5))∣
⇒
2
1
∣(4+3+(−25)∣
=
2
1
∣(−25+7)∣
=
2
1
∣(−18)∣
Area of triangle =9 cm
Answered by
0
Answer:
Area of triangle=
2
1
∣(x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
))∣ where x=1,x
2
=3,x
3
=5, y
1
=2,y
2
=7,y
3
=3
⇒
2
1
∣(1(7−3)+3(3−2)+5(2−7))∣
⇒
2
1
∣(1−(4)+3(1)+5(−5))∣
⇒
2
1
∣(4+3+(−25)∣
=
2
1
∣(−25+7)∣
=
2
1
∣(−18)∣
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