Question

i
26. A rocket burns 0-25 kg of fuel per second and ejects it as a gas with a velocity of 1 km/s. Calculate
the force exerted by the ejected gas on the rocket.
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Answer 1

Answer:

Explanation:

for rocket propelsion differntial equation is

f=mdv/dt+vdm/dt

here

dm/dt=0.25kg/s

v=1km/s-----(but N=newton is kgm/s² so we have to change the velocity in m/s)

v=1×10³m/s

then

f=md(1)/dt+(1)dm/dt

f=0+1×0.25×10³.........we know that thedifferentiaton of constant =0 so dv/dt=0

f=250N