Find the area of the triangle whose vertices are : (2,3), (-1,0), (2,-4)
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Answered by
4
area of triangle=1/2 [{2 (0+4)}+{(-1 )(-4-3)}+{2 (3-0)]
=1/2 (8+7+6)
=1/2×21
=21/2
=1/2 (8+7+6)
=1/2×21
=21/2
Answered by
5
Hey friend !
Here's your answer.
formula -
1/2 [ x1 (y2-y3) + x2 (y3-y1) + x3 (y1-y2) ]
1/2 [ 2 (0+4) + (-1) (-4-3) + 2 (3-0)
1/2 (8 + 7 + 6)
21/2 square units
____________________________
Hope this helps !
Here's your answer.
formula -
1/2 [ x1 (y2-y3) + x2 (y3-y1) + x3 (y1-y2) ]
1/2 [ 2 (0+4) + (-1) (-4-3) + 2 (3-0)
1/2 (8 + 7 + 6)
21/2 square units
____________________________
Hope this helps !
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