Question

find the area of the triangle whose vertices are (-3,5) (5,6) and(5,-2)​

Answer 1

32 cm sq is the answer of urs question.

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Answer 2

The area of the  triangle whose vertices are (-3,5) (5,6) and(5,-2)​ is 32 cm².

Step-by-step explanation:

Given vertices of triangle are :

A (x₁ , y₁) = (-3,5)

B (x₂,y₂) = (5,6)

C (x₃,y₃) = (5,-2)

=> Area of triangle will be :

$Area = \frac{1}{2}|x_{1}(y_{2}-y_{3}) + x_{2}(y_{3}-y_{1}+ x_{3}(y_{1}-y_{2})| \\\\Area = \frac{1}{2}|-3(6+2)+5(-2-5)+5(5-6)|\\\\Area = \frac{1}{2}|-3(8)+5(-7)+5(-1)|\\\\Area = \frac{1}{2}|-24-35-5|\\\\Area = \frac{1}{2}|-64|\\\\Area = \frac{1}{2}(64)\\\\Area = 32 \ cm^{2}$

=> The area of the triangle given is 32 cm².