Find the area of the triangle whose vertices are (-5,1) (3,-5) (5,2)
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Answered by
3
Answer:
32
Step-by-step explanation:
Let A(-5,-1), B(3,-5), C(5,2)
Here, x1 = -5 , y1 = -1 , x2 = 3 , y2 = -5 , x3 = 5 , y3 = 2
Area of triangle = 1/2 * ( x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2) )
Substituting the values in the given formula you get
Area of the triangle ABC = 32
Answered by
2
Answer:
hope its helps u dear.........
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