Question

find the area of the triangle with perimeter 22cm one side 9 cm and difference of other side is 5 cm​

Answer 1

Let the other side be x.

Perimeter of triangle =Sum of all sides of triangle

Perimeter =9+x+x+5

22=14+2x

2x=22-14

2x=8

x=4 cm

x+5=4+5=9cn

Area of triangle =1/2*base*height

Area=1/2*4*5

Area=10cm^2

Answer 2

Answer:

area = 13.26 cm sq.

Step-by-step explanation:

explanation is in the 3 pics.