Find the area of the triangle with vertices (0,0),(6,0),(0,5)
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Answered by
4
Solution
According to distance formula, length of segment is √[(x2 - x1)² + (y2 - y1)²].
AB = √[(6 - 0)² + (0 - 0)²] = 6
BC = √[(6 - 0)² + (0 - 5)²] = √61
CA = √[(0 - 0)² + (5 - 0)²] = 5
Now, if we understand the pattern then:
→ √61² = 5² + 6²
→ H² = B² + P²
Hence ABC is a right angles ∆.
Area of right ∆ = ½ × base × height
→ ½ × 5 × 6
→ 15 unit²
Answer: 15 unit²
Answered by
7
Step-by-step explanation:
the formula to find the area of triangle when coordinates of vertices are given,
▶Area of triangle =
| Ax(By-Cy)+Bx(Cy-Ay) + Cx (Ay-By)|/2
▶let the coordinates of vertices are,
A(0,0) = (Ax , Ay)
B(6,0) = (Bx, By)
C(0,5) = (Cx, Cy)
so the are of given triangle
= |Ax(By-Cy)+Bx(Cy-Ay) + Cx (Ay-By)|/2
=|0(0 - 5)+6(5 - 0)+0(0 - 0)| / 2
=|0 + 6 x 5 + 0 | / 2
=30 /2
=15
therefor are of triangle is
15 squnit
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