Question

❋ Find the Area of the Triangular field of sides 55 m, 60 m, and 65 m. Find the cost of laying the grass in the triangular field at the rate of Rs 8 per m²

❌don't spam​

Answer 1

Answer:

Hi dear blink hope this helps you have a great day ahead

Step-by-step explanation:

∴ The cost of laying the grass in the triangular field at the rate of Rs 8 per m² is Rs.12296.32.

Answer 2

Step-by-step explanation:

$\sf \: Solution:$

Given that 

Sides of the triangular field are

• 50 m
• 60 m
• 65 m

Cost of laying grass in a triangular field

= Rs 8 per m2

Let a = 55, b = 60, c = 65

$\bold {Semi- Perimeter = \frac{(a + b + c)}{2} } \\ \\ \sf \:⇒ s = \frac{(55 + 60 + 65)}{2} = \frac{180}{2} = 90.$

By using Heron’s formula,

Area of ΔBEC

$\sf= \sqrt{ s(s−a)(s−b)(s−c)} \\ \\ \sf \: = \sqrt{90(90−55)(90−60)(90−65)} \\ \\ \sf \: = \sqrt{90 \times 35 \times 30 \times 25} \\ \\ \sf \: = \sqrt{2362500} \\ \\ \sf \red{= 1537 {m}^{2} }$

Now, Cost of laying grass

= Area of triangle × Cost of laying grass per m2

= 1537×8

= Rs.12296

More info :-

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} {\boxed{\begin{array}{cc} {\sf{Area \: of \: parallelogram = Base × Altitude }} \\ \\ \sf{ Area \: of \: rectangle = Length × breadth}\\ \\ \sf{ Area \: of \: square = Side × Side } \\ \\ \sf{Area \: of \: cylinder's \: surface = 2πr(h + r)} \\ \end{array}}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered} \end{gathered}$