find the area of trapezium
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BY PHYTHAGORAS THEORAM FIND THE HEIGHT
H^2=P^2+B^2
17^2=P^2+8^2
289=P^2+64
289-64=P^2
225=P^2
P=√225
P=15 CM HEIGHT WILL THIS
THAN
AREA OF TRAPEZIUM=1/2×(6+14)×15
=1/2×20×15
=10× 15 KYUNKI 2 KO 20 SE KATA TO BACHA 10
=150CM^2 THIS IS THE ANSWER
PLEASE MARK ME AS A BRAINLIST
H^2=P^2+B^2
17^2=P^2+8^2
289=P^2+64
289-64=P^2
225=P^2
P=√225
P=15 CM HEIGHT WILL THIS
THAN
AREA OF TRAPEZIUM=1/2×(6+14)×15
=1/2×20×15
=10× 15 KYUNKI 2 KO 20 SE KATA TO BACHA 10
=150CM^2 THIS IS THE ANSWER
PLEASE MARK ME AS A BRAINLIST
mannishh:
bro please mark me as a brainlist
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