Find the area of trapezium ABCD ;AB|| DC in which AB=9cm ,DC=4cm, AD=5cm and BC=5cm
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area of trapezium=1/2 (a+b)height
= 1/2(9+4)5
=1/2×13×5
=32.5
so,area of trapezium is 32.5
= 1/2(9+4)5
=1/2×13×5
=32.5
so,area of trapezium is 32.5
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