find the area of trapezium ABCD as given in the figure in which ADCE is rectangle (hint:ABCD has two parts)
AB=3CM ,AD=8CM,ED=3CM
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Area of trapezium = 1/2 × sum of parallel sides × height
Area= 1/2 × ( 3 + 8 ) × 3
= 1/2 × 11 × 3
= 33 / 2 cm^2
= 16.5 cm^2 Anss
Area= 1/2 × ( 3 + 8 ) × 3
= 1/2 × 11 × 3
= 33 / 2 cm^2
= 16.5 cm^2 Anss
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