in the given figure ,if x= 3y, find the value of x,y and z ?
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tourister60:
its showing x= 45 y=15 z=40
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x=3y
so 3y+y+120=180
4y=180-120
y=60÷4
y=15
x=15×3
x=45
qsr+z+80=180
60+z+80=180
z=40
so 3y+y+120=180
4y=180-120
y=60÷4
y=15
x=15×3
x=45
qsr+z+80=180
60+z+80=180
z=40
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