Question

find the area of trapezium where base are 20 and 18 and the distance between their two sides are 12 cm​

Answer 1

Step-by-step explanation:

$area \: of \: trapezium \: = \frac{1}{2} (the \: sum \: of \: two \: parellalr \: line) \times \times height$

$\frac{1}{2} = (20 + 18) \times 12 \\ \frac{1}{2} = 38 \times 12 \\ 19 \times 12 = 228 \\ area \: of \: trapezium = 228sqcm.$