Question

find the area of trapezium whose parallel sides are 10 cm and 2 metre and its altitude its 1.5 m

Answer 1

We know that area of trapezium is
$1 \div 2(sum \: of \: parallel \: sides) \times distance \: between \: them$
$1 \div 2(10 + 2) \times 1.5$
$1 \div 2(12) \times 1.5$
$6 \times 1.5$
$= 9 {cm}^{2}$

Answer 2

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