write a equation of a line on which the point (a,a) lies
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equation y = mx + c
where m= slope and c= intercept
(x,y)=(a,a)
then
a = m(a)+c
a(1-m)=c
where m= slope and c= intercept
(x,y)=(a,a)
then
a = m(a)+c
a(1-m)=c
Nishant324:
plz help me in other question s
Answered by
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general eq of line is y = mx + c
this pass through ( a,a )
=> a = ma + c
=> c = a(1-m)
=> eq of line is y = mx + a(1-m)
where m is slope of line
this pass through ( a,a )
=> a = ma + c
=> c = a(1-m)
=> eq of line is y = mx + a(1-m)
where m is slope of line
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