Question

find the area of trapezium whose parallel sides are 14cm and 10cm and whose height is 6cm​

Answer 1

Ello..✌✌

We know that, Area of Trapezium

A = (a+b)/2 × h

So, A = (14 + 10)/2 × 6

A = 24/2 × 6

A = 12 × 6

A = 72 cm square

Answer 2

Question : Find the area of trapezium whose parallel sides are 14cm and 10cm and whose height is 6cm.

$\fbox{\underline{\underline {Solution}}}$

$\fbox {\text{Area\: of \:trapezium = \frac{1}{2}\times sum \:of \:parallel \:sides \times height }}$

$Area\: of \:trapezium = \frac{1}{2} \times sum \: of \: parallel \: sides \times height$

$Area\: of \:trapezium = \frac{1}{2} \times (14\: cm+10\:cm)\times 6 \:cm$

$Area\: of \:trapezium = \frac{1}{2} \times 24\: cm \times 6 \:cm$

$Area\: of \:trapezium = (24 \times 3) \: {cm}^{2}$

$\fbox {\text{Area\: of \:trapezium= 72 \: cm^2 }}$

Area of some more figure :

$\fbox{\text {Area\: of \:square= {side}^{2} }}$

$\fbox {\text{Area\: of \:triangle = \frac{1}{2}\times base \times height }}$

$\fbox {\text{Area\: of \:right\:triangle = \frac{1}{2}\times product\: of\: its\: legs }}$