Question

find the area of trapezium whose parallel sides are 24cm and 20 cm and distence between them is 15 cm​

Answer 1

Answer:

We know,

Area of trapezium= 21

×Sum of parallel sides×Distance between them.

Area of trapezium = 2h

(a+b), where a and b are base and h is height.

Here, a=24 cm, b=20 cm and h=15 cm

Therefore, Area= 2/15

(24+20)=330cm²

Answer 2

Given : Parallel sides of a trapezium are 24cm and 20cm and distance between them is 15cm.

To Find : Area of the trapezium.

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Here

$\: \:$

• Parallel sides of the trapezium = 24cm and 20cm
• Distance between the parallel sides = 15cm

$\: \:$

As we know that

$\:$

$\underline{\boxed{\sf\purple{\bigstar \: area \: of \: a \: trapezium = \frac{1}{2} \times sum \: of \: parallel \: sides \: \times distance }}}$

$\:$

Put the values in the formula -

$\: \:$

$\tt:\implies \: area \: of \: the \: trapezium = \dfrac{1}{2} \times (24 + 20) \times 15 \\ \\ \\ \tt:\implies \: area \: of \: the \: trapezium \: = \frac{1}{\cancel{2}} \times \cancel{44}\times 15 \\ \\ \\ \tt:\implies \: area \: of \: the \: trapezium \: = 22 \times 15 \\ \\ \\ \tt:\implies \: area \: of \: the \: trapezium \: = \underline{\boxed{\tt\purple{330 {cm}^{2} }}}\bigstar \\ \\ \\ \\ \sf\therefore{\underline{Hence, \: the \: area \: of \: the \: trapezium \: is \: \bold{330 {cm}.}^{2} }}$