Question

QUESTION ❓

Find the value of p(y) = 2y³ - 2y + √7 for y = -2
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Answer 1

Answer:

root7-12

Step-by-step explanation:

p(y) =2y³-2y+root7

p(-2) =2(-2)³-2(-2)+root7

0 =-16+4+root7

0 =root7-12

Answer 2

$\huge \rm \underline\red{A} \underline\blue{n} \underline \pink{s} \underline\green{w} \underline\orange{e} \underline\purple{r}$

p (y) = 2y³ - 2y + √7

∴ p (-2) = 2 × (-2) -2 × (-2) +√7

= 2 × (-8) -2 × (-2) + √7

= -16 + 4 + √7

= -12 + √7

∴ For y = -2 the value of polynomial is -12 + √7.