Question

find the area of trapezium whose parallel sides are 8 cm and 12 CM and perpendicular distance between them is 32cm (solve it in proper method)​

Answer 1

Answer:

320 cm square

Step-by-step explanation:

let us assume AB and CD are parallel side of trapezium where AB = 8 cm, CD = 12 cm And perpendicular distance is height (h) = 32 cm

as we know area of trapezium is

1/2(sum of parallel side) * h

1/2( 8+12) *32

1/2*20 *32

1*10*32 = 320 cm square

hence area of trapezium = 320 cm square

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