Question

find the area of trapezium whose parallel sides are length 12 cm and 15 cm and the distance between them is 15 CM​

Answer 1

Answer:

Area of a trapezium = $\huge \frac {h}{2}$ *(a+b)

Area = $\huge \frac {15}{2}$ *(12+15)

Area = $\huge \frac {15}{2}$ * 27

Area = 202.5sq.cm

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Answer 2

Answer:

$area = a + b \div 2 \times h$

Step-by-step explanation:

$12 + 15 \div 2 \times 15$

$13.5 \times 15 =$

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