Find the area of trapezium whose parallel sides of length 10 cm and 15 cm are at a distance of 6 cm from each other calculate this area as the sum of the areas of two triangles and one rectangle
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area =1/2*sum of parallel side *distance between them =1/2*(10+15)*6=75cm sq then draw perpendicular from up on the base then there are two triangle of heights 6cm and base 2.5cm and a rectangle of l=10 and b=6
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