Question

Find the area of trapezium with parallel sides 5m and 2m and perpendicular distance between
them is 4m.

Answer 1

Step-by-step explanation:

Let the common ration be x,

Then the two parallel sides are 3x, 2x

Distance between them = 10 cm

Area of trapezium = 325 cm²

Area of trapezium = 1/2 (p₁ + p₂) h

325 = 1/2 (3x + 2x) 10

⇒ 325 = 5x × 5

⇒ 325 = 25x

⇒ x = 325/25

Therefore, 3x = 3 × 13 = 39 and 2x = 2 × 13 = 26

Therefore, the length of parallel sides area are 26 cm and 39 cm.

Answer 2

${\huge{\underline{\underline{\frak{Question}}}}}$

★ Find the area of trapezium with parallel sides 5m and 2m and perpendicular distance between them is 4m .

${\huge{\underline{\underline{\frak{Solution\checkmark}}}}}$

★ Given :

• Parallel sides of trapezium = 5m and 2m
• Perpendicular distance between sides = 4m

★ To Find :

• The area of trapezium = ?

★ Solution :

Using the Formula -

$\star \boxed{ \rm \: area \: of \: trapezium = \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height}$

$\mapsto \rm \: area_{trapezium} = \frac{1}{ \cancel2} \times (2m + 5m) \times \cancel4m$

$\mapsto \rm \: area _{trapezium} = 7m \times 2m$

$\mapsto \boxed{\rm \: area_{trapezium} = 14 {m}^{2} }$

The area of this trapezium would be 14m² .

★ Important Points :

• A trapezium is a Quadrilateral .
• The unit of area is always in square (unit²) .
• Area of trapezium =
• $\rm \frac{1}{2} \times (sum \: of \: parallel \: sides) \times height$
• Perimeter of trapezium = Sum of all sides .