Question

find the area of trepezium whose parallel sides are 80 m and 56 m and the distance between them is 30 m.​

Answer 1

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• Parallel sides = 80m and 56m
• Distance btw parallel sides = 30m

______________________

$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Area of trapezium = ??

______________________

$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

$\sf{\red{\boxed{\bold{area = \dfrac{1}{2}\times ( sum\: of \: parllel\: sides) \times height}}}}$

⠀⠀⠀⠀

$\sf : \implies\:{\bold{ Area = \dfrac{1}{2} \times ( 80 + 56 )\times 30}}$

⠀⠀⠀⠀

$\sf : \implies\:{\bold{ Area = \dfrac{1}{2} \times 136 \times 30}}$

⠀⠀⠀⠀

$\sf : \implies\:{\bold{ Area = {1} \times 68 \times 30}}$

⠀⠀⠀⠀

$\sf : \implies\:{\bold{ Area = 2040m^2 }}$

______________________

$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Area of trapezium is 2040 m^2

____________________________

⠀⠀⠀⠀

⠀⠀⠀⠀

More about trapezium :-

• It has only one pair of parallel side
• It is an example of convex polygon .
• It has 4 edges and 4 vertices

Answer 2

Answer:

Given -

• Parallel sides of the trapezium = 80 m and 56 m.
• Distance between them = 30 m

To find -

• Area of trapezium.

Solution

$\\ \sf \small \: Area \: \: of \: \: trapezium = \frac{1}{2} \times (sum \: of \: sides) \: \times (distance \: \\ \\ \sf \small between \: parallel \: sides) \\ \\ \\ \implies \sf \: \frac{1}{2} \times (80 + 56) \times 30 \\ \\ \\ \implies \sf \: 136 \times 30 \\ \\ \\ \implies \sf \: 2040 \: {m}^{2}$

$\dag$ $\large{\underline{\boxed{\bf{Area\:\:of\:\: trapezium=2040 m^2}}}}$