Question

find the area of triangle 13,14,16.using heron's formula​

Answer 1

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Answer 2

Answer:

a=13,b=14, c=15

s=13+14+15/2=42/2=21

a=

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{21(21 - 13)(21 - 14)(21 - 15)}$

$\sqrt{21 \times 7 \times 6 \times 8}$

$\sqrt{3 \times 7 \times 7 \times 2 \times 3 \times 4 \times 2}$

$3 \times 7 \times 2 \sqrt{4}$

$42 \sqrt{7}$

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