find the area of triangle
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here is your answer.
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x1y1 = 2,0.
x2y2 = -1,3.
x3y3 = 2,4.
Ar of ∆. = 1/2 { x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y2 - y1 ) }.
1/2 { 2 ( 3-4) - 1 ( 4 -0 ) + 2 (3 -0 )
1/2 { 2 (-1) - 1 (4) + 2 (3)
1/2 { -2 - 4 +6 }
1/2 { -6 +6}
1/2 {0} .
0..
I hope it help you...
x2y2 = -1,3.
x3y3 = 2,4.
Ar of ∆. = 1/2 { x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y2 - y1 ) }.
1/2 { 2 ( 3-4) - 1 ( 4 -0 ) + 2 (3 -0 )
1/2 { 2 (-1) - 1 (4) + 2 (3)
1/2 { -2 - 4 +6 }
1/2 { -6 +6}
1/2 {0} .
0..
I hope it help you...
saiagarwal707:
Your answer is wrong
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