Question

Find the area of triangle ABC formed by the points A (0, 4), (3, 0) and X (4, 0) and show these points on coordinate axis.​

Answer 1

Explanation:

By distance formula:

AC=

0

2

+4

2

=4

AB=

3

2

+0

2

=4

BC=

3

2

+(−4)

2

=5

And s=

2

3+4+5

=6

So area of ΔABC=

6(6−5)(6−4)(6−3)

=

6×1×2×3

=6