Question

Find the area of triangle ABC where AB is 9 cm and BC is 40 cm and Angle AB is 90°​

Answer 1

Answer:

139°

Step-by-step explanation:

Area of triangle = A + B +C

= 9 + 40 + 90

= 139°

Answer 2

Answer:

Given - AB =9 cm, BC = 50 cm, angle ABC = 90°

To find - Area of ∆ABC

Solution-

Area of a right ∆ABC =

$\frac{1}{2} \times base \: \times \: height$

$\frac{1}{2} \times 50 \times 9$

$25 \times 9$

$800 \: {cm}^{2}$

Hope it helps u

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