Find the area of triangle ABC whose vertices are A(-5,7) ,B(-4,-5) and C (4,5). Calculate the length of sides of triangle using a graph. (These vertices should be marked in graph)
Answers
Answered by
0
Answer:
area of triangle 53 sq units
Step-by-step explanation:
area =
= 1/2 [x1 {y2-y3}+x2{y3-y1}+x3{y1-y2}
=1/2{-5}{-5-5}+[-4}[2-7}=4{7-{5}]
=1/2*{106}
=53 unit sq
Answered by
0
Answer:
karthik the answer is 53
Step-by-step explanation:
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