Math, asked by karthiksrinivas20061, 7 months ago

Find the area of triangle ABC whose vertices are A(-5,7) ,B(-4,-5) and C (4,5). Calculate the length of sides of triangle using a graph. (These vertices should be marked in graph)

Answers

Answered by rajkumarewa
0

Answer:

area of triangle 53 sq units

Step-by-step explanation:

area =

= 1/2 [x1 {y2-y3}+x2{y3-y1}+x3{y1-y2}

=1/2{-5}{-5-5}+[-4}[2-7}=4{7-{5}]

=1/2*{106}

=53 unit sq

Answered by jerinsejov
0

Answer:

karthik the answer is 53

Step-by-step explanation:

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