Question

Find the area of triangle formed by points A(1,-2), B(2,3) and C(-4,-3). Also find the length of altitude from C(-4,-3) on side AB.​

Answer 1

Answer:

Given information is :

ABCD is a parallelogram

A (1,-2), B (2,3), C(-3.2), D(-4,-3)

AB is the base

Next we find out the equation of line AB.

According to two points formula, equation of a line passing through two points (x1,y1) and (x2,y2) is

y−y2=y1−y2x1−x2(x−x2)

Therefore taking the points (1,-2) and (2,3), equation of AB is

y−3=(−2−3)1−2(x−2)

⟹y−3=−5−1(x−2)

⟹y−3=5(x−2)

⟹y−3=5x−10

⟹5x−y−7=0

From the figure, we can see that the height of the parallelogram is the perpendicular distance of point C from line AB.

Distance (d) of a point (x1,y1) from a line ax+by+c=0 is given by the formula

d=|ax1+by1+c|a2+b2√

Here, (x1,y1)isC(−2,3),a=5,b=−1,c=−7

Hence height,h=|5(−3)−1(2)−7|52+(−1)2√

⟹h=|−15−2−7|25+1√

⟹h=|−24|26√

⟹h=2426√

Rationalising, we get

⟹h=2426√26

⟹h=121326−−√

MARK AS BRAINLIEST

Answer 2

Answer:

Step-by-step explanation:

Hope it help you