find the area of triangle formed by the point (-5,7),(-4,-5)and(4,5)
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Solution
Area= 1/2|{x1(y2-y3)+ x2(y3-y1)+ x3(y1-y2)}|
= 1/2 { -5(-5-5)+ (-4) (5-7)+ 4(7-(-5))}
= 1/2 { 50+ 8+ 48}
= 1/2* 106
= 53 sq.unit.
_____________
HOPE IT IS SATISFACTORY☺☺☺
Area= 1/2|{x1(y2-y3)+ x2(y3-y1)+ x3(y1-y2)}|
= 1/2 { -5(-5-5)+ (-4) (5-7)+ 4(7-(-5))}
= 1/2 { 50+ 8+ 48}
= 1/2* 106
= 53 sq.unit.
_____________
HOPE IT IS SATISFACTORY☺☺☺
arumugamleylanowruoq:
thank u
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