find the area of triangle formed by the point p(-1.5,3) .q(6.-2)and r(-3.4)
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3
Answer:
ok
Explanation:
Given P(−1.5,3),Q(6,−2) and R(−3,4)
Therefore, area is given by
=
2
1
×[(−1.5)(−2−4)+6(4−3)+(−3)(3+2)]
=
2
1
×(9+6−15)
=0
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