Question

find the area of triangle having vertices at (8,1) ,(1,-4),(4,-5)​

Answer 1

Answer:

Area of triangle = 13 sq units

Step-by-step explanation:

triangle having vertices at (8,1) ,(1,-4),(4,-5)​

x₁ = 8  y₁ = 1

x₂ = 1  y₂ = -4

x₃ = 4  y₃ = -5

Area of Triangle = (1/2) | x₁(y₂ - y₃)  + x₂(y₃ - y₁) + x₃(y₁ - y₂) |

= (1/2) | 8(-4 -(-5)) + 1(-5 - 1) + 4(1 - (-4))|

= (1/2) | 8  - 6 + 24 |

= (1/2) 26

= 13

Area of triangle = 13 sq units