find the area of triangle region with verticles (1,2),(3,0) and orgin
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Answer:
Given :
Vertices of triangle given :A(1,2),(3,0) &(0,0)
To Find :
Area of Triangle
____________________________________________
Origin means those points or lines which passes through neither x axis or y axis but through( 0,0)
\bold{\boxed{Area \: of \: an \: Triangle = \frac{ |Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By)| }{2}}}
AreaofanTriangle=
2
∣Ax(By−Cy)+Bx(Cy−Ay)+Cx(Ay−By)∣
Area \: of \: Triangle = \frac{ |1(0 - 0) + 3(0 - 2) + 0(2 - 0)| }{2}AreaofTriangle=
2
∣1(0−0)+3(0−2)+0(2−0)∣
= \frac{ |0 - 6 + 0| }{2} = \frac{6}{2} = 3 sq.units=
2
∣0−6+0∣
=
2
6
=3sq.units
Hope you all understand it.
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