find the area of triangle sides
12cm, 12cm and 6cm by Hexor's
formula
Answers
Answer:
34.85 CM²
Step-by-step explanation:
The given sides are 12cm, 6cm and 12cm.
Let a = 12 cm
b = 6 cm
c = 12 cm
Semi-perimeter =( a + b + c) / 2
=( 12+6+12)/2
= 15
So, s=15
Therefore,Area = √s(s-a) (s-b) (s-c)
= √15(15-12) (15-6) (15-12)
= √15×3×9×3
=9√15
= 34.8568501 cm²
Hope it will help you
sides are 12cm, 12cm and 6 cm
s=sum of sides /2
=12+12+6/2
=15 cm
s-a = 15-12=3c
s-b= 15-12= 3cm
s-c= 15-6= 9cm
area of triangle=under root (s(s-a)(s-b)(s-c))
= under root (15×3×3×9)
= under root (3×5×3×3×3×3)
= 3×3 under root (3×5)
= 9 under root 15cm square Answer.