Math, asked by goswamienterprises72, 4 months ago

find the area of triangle sides
12cm, 12cm and 6cm by Hexor's
formula​

Answers

Answered by Jenish9798
0

Answer:

34.85 CM²

Step-by-step explanation:

The given sides are 12cm, 6cm and 12cm.

Let a = 12 cm

b = 6 cm

c = 12 cm

Semi-perimeter =( a + b + c) / 2

=( 12+6+12)/2

= 15

So, s=15

Therefore,Area = √s(s-a) (s-b) (s-c)

= √15(15-12) (15-6) (15-12)

= √15×3×9×3

=9√15

= 34.8568501 cm²

Hope it will help you

Answered by itikasinghal1602
0

sides are 12cm, 12cm and 6 cm

s=sum of sides /2

=12+12+6/2

=15 cm

s-a = 15-12=3c

s-b= 15-12= 3cm

s-c= 15-6= 9cm

area of triangle=under root (s(s-a)(s-b)(s-c))

= under root (15×3×3×9)

= under root (3×5×3×3×3×3)

= 3×3 under root (3×5)

= 9 under root 15cm square Answer.

Similar questions