Find the area of triangle two sides of triangle are 18 cm and 10 cm and the perimeter is 42 cm
jsdcorreo:
69.65cm² -- http://triancal.esy.es/?a=18&b=10&p=42
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hello friend
ATQ
here a = 18 ,b = 10 c = ?
perimeter = 42
P = a + b+ c
42 = 18 +10 + c
42 - 28 = c
..................... c= 14
Using Heron's formula,
S = a+ b + c/2 = P / 2 = 42/ 2 = 21
s- a = 21-18 = 3
s- b = 21 -10= 11
s-c = 21-14 = 7
A = ✓ S (s- a) (s- b) ( s-c)
= ✓ 21 × 3 × 11 × 7
=. 21 ✓ 11 cm².......... Ans......
hope it helps you
ATQ
here a = 18 ,b = 10 c = ?
perimeter = 42
P = a + b+ c
42 = 18 +10 + c
42 - 28 = c
..................... c= 14
Using Heron's formula,
S = a+ b + c/2 = P / 2 = 42/ 2 = 21
s- a = 21-18 = 3
s- b = 21 -10= 11
s-c = 21-14 = 7
A = ✓ S (s- a) (s- b) ( s-c)
= ✓ 21 × 3 × 11 × 7
=. 21 ✓ 11 cm².......... Ans......
hope it helps you
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