Question

Find the area of triangle whase vertexs of(1.2) (3.4) (5.7)

Answer 1

Answer:

• Area of triangle = 1 sq. unit.

Step-by-step explanation:

Given:

• Vertex of triangle A(1, 2), B(3,4) and C(5, 7).

To Find:

• Area of triangle.

We know that,

$\longrightarrow \bf Area\;of\;triangle=\dfrac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$

Where,

• x₁ = 1 and y₁ = 2
• x₂ = 3 and y₂ = 4
• x₃ = 5 and y₃ = 7

Put the values in the formula,

$\longrightarrow \bf Area\;of\;triangle=\dfrac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]\\ \\ \\ \longrightarrow \sf Area\;of\;triangle=\dfrac{1}{2}[1(4-7)+3(7-2)+5(2-4)] \\ \\ \\ \longrightarrow \sf Area\;of\;triangle=\dfrac{1}{2}[-3+15-10]\\ \\ \\ \longrightarrow \sf Area\;of\;triangle= \dfrac{1}{2}\times 2\\ \\ \\ \longrightarrow \sf Area\;of\;triangle=1\;sq.\;unit.$

Hence, area of triangle = 1 sq. unit.

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