Question

Find the area of triangle when it's 2 sides 18cm, 10cm are given and perimeter = 42cm.

Answer 1

HEY MATE HERE IS YOUR ANSWER

First sides (a) = 18cm
second side (b) = 10 cm

Third side = sum of two sides - perimeter
= 18+10-42 = 14 cm

a+b+c/2 = semiperimeter (s)

18+10+14/2 = 42/2 = 21cm

BY heron's formula

-/s (s-a) (s-b) (s-c)

under root 21 (21-18) (21-10) (21-14)

under root 21 (3) (11) (7)

under root 7×3× (3) ×11×7


7×3root 11

21 root 11 cm^2

HOPES THIS HELPS YOU.........☺☺

Answer 2

triangle 2 sides are 18cm, 10cm
perimeter 42 cm
one side = 42-(18+10) cm
= 14 cm
half perimeter = 42/2 = 21 cm
area of triangle =√{21(21-18)(21-10)(21-14)}
=√{21×3×11×7}
=3×7√11
=21√11 cm2