Question

find the area of triangle where a=40 cm b=24cm and c=32cm​

Answer 1

Answer:

48cm^2

Step-by-step explanation:

s=a+b+c/2

s=40+24+32/2

s=96/2

s=48cm^2

Answer 2

Step-by-step explanation:

a= 40cm

b=24cm

c=32cm

s= (a+b+c)/2= (40+24+32)/2

s= 96/2= 48

now putting heron's formula, we get

√s(s-a)(s-b)(s-c)

√48(48-40)(48-24)(48-32)

√(2*2*2*2*3)(2*2*2)(2*2*2*3)(2*2*2*2)

2*2*2*2*2*2*2*3

16*24

384 cm²