Question

find the area of triangle which the straight line 3x+4y-7=0 makes with the coordinate axes

Answer 1

equation = 3x+4y-7=0
the straight line equation can be written as
x/(7/3)+y/(7/4)=1, 
where 7/3 = x- intercept
and 7/4 is y intercept
so, area of triangle= 1/2 ( base×height)
                              = 1/2((7/3)×(7/4))
                              =49/24
area = 49/24 square units

hope you understand :)

Answer 2

Answer:

49/24

Step-by-step explanation:

equation = 3x+4y-7=0

the straight line equation can be written as

x/(7/3)+y/(7/4)=1,  

where 7/3 = x- intercept

and 7/4 is y intercept

so, area of triangle= 1/2 ( base×height)

                             = 1/2((7/3)×(7/4))

                             =49/24

area = 49/24 square units

hope you understand :)