Question

Find the
area of triangle whose base and altitude are 8th cm and 5cm.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$20 \: {cm}^{2}$

Step-by-step explanation:

$area \: of \: triangle \: = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 8 \times 5 \\ = \frac{40}{2} \\ = 20 \: {cm}^{2}$