Question

If potential energy is double of kinetic energy of an object mass 10 kg , moving with
velocity 10 m/s .find the height of object?
If pressure exerted on earth is 1 atmospheric pressure. calculate force acting on one​

Answer 1

QUESTION 1 :-

If potential energy is double of kinetic energy of an object mass 10 kg , moving with

velocity 10 m/s .find the height of object?

_______________________

Given :

Mass of object = 10 kg

Velocity = 10 m/s

To find :

the height of object

Formula used :

$\bf p = mgh$

$\bf k = \frac{1}{2} \times m \times {v}^{2}$

Where :-

• p = potential energy
• k = kinetic energy
• m = mass of object
• v = velocity
• h = height

Solution :

Potential energy is double of kinetic energy.

$\sf\therefore mgh = 2 \times \dfrac{1}{2} \times m \times {v}^{2}$$\sf\implies mgh = m \times {v}^{2}$

cancel out m from each side.

$\sf\implies gh = {v}^{2}$

Now g = 10 m/s²

$\sf\implies 10 \times h = {v}^{2}$

Now put v = 10 m/s ( given )

$\sf\implies 10 \times h = {10}^{2}$

$\sf\implies h = \dfrac{{10}^{2}}{10}$$\sf\implies h = \dfrac{{10} \times 10}{10}$

$\sf\implies h = 10m$

Answer 1 :

height = 10 metres

___________________

QUESTION 2 -

If pressure exerted on earth is 1 atmospheric pressure. calculate force acting on one square metre.

Solution :-

1 atm = 101325 Pa

Area = 1 m²

Where :-

• atm = atmospheric pressure
• Pa = Pascal

$\sf p = \dfrac{f}{a}$

where :-

• p = pressure
• f = force
• a = area

$\sf \implies 101325= \dfrac{f}{1}$

$\sf \implies 101325 \: N = {f}$

Answer 2 :

• 101325 N

Answer 2

QUESTION - 1

If potential energy is double of kinetic energy of an object mass 10 kg , moving with

velocity 10 m/s .find the height of object?

Formula -

$\bf p = mghp=mgh$

$\bf k = \frac{1}{2} \times m \times {v}^{2}$

Where :-

• p = potential energy
• k = kinetic energy
• m = mass of object
• v = velocity
• h = height
• Potential energy is double of kinetic energy.

$\sf\therefore mgh = 2 \times \dfrac{1}{2} \times m \times {v}^{2}$

$\sf\implies mgh = m \times {v}^{2}$

Now

cancel out m from each side-

$\sf\implies gh = {v}^{2}$

Now g = 10 m/s²

$\sf\implies 10 \times h = {v}^{2}$

Now put v = 10 m/s ( given )

$\sf\implies 10 \times h = {10}^{2}$

$\sf\implies h = \dfrac{{10}^{2}}{10}$

$\sf\implies h = \dfrac{{10} \times 10}{10}$

⟹h=10m

___________________

QUESTION 2 -

If pressure exerted on earth is 1 atmospheric pressure. calculate force acting on one square metre.

Solution :-

1 atm = 101325 Pa

Area = 1 m²

Where :-

• atm = atmospheric pressure

Pa = Pascal

$\sf p = \dfrac{f}{a}$

where :-

• p = pressure
• f = force
• a = area

$\sf \implies 101325= \dfrac{f}{1}$

$\sf \implies 101325 \: N = {f}$

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