Question

Find the area of triangle whose base is 14cm and height is 5cm?
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Answer 1

Answer:

A=1/2 b× h

= 1/2 × 14 ×5

= 7×5=35 cm ^2

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Answer 2

The area of the triangle is $35 cm^{2} .$

• A triangle in the subject of geometry is a polygon which has three sides and is a figure with three edges and three vertices.
• If ABC is a triangle, it is written as triangle ABC, where A, B, and C represent the triangle's vertices. In Euclidean geometry, a triangle is a shape that is two-dimensional  and which is represented by three non-collinear points in a single plane.
• A scalene triangle is a particular kind of triangle in which each of the three sides has a unique side length. The three angles differ completely from one another as a result of this.
• Two sides of an isosceles triangle are of equal length. The two angles that are in opposition to the two equal sides are also equal.
• All three sides of an equilateral triangle are equal to one another.

Here, according to the given information,

The base = 14 cm.

The height = 5 cm.

We know that, area of the triangle = $\frac{1}{2} .base.height$

Then, we get,

Area of the triangle = $\frac{1}{2} .14.5 = 35 cm^{2} .$

Hence, the area of the triangle is $35 cm^{2} .$

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