Question

Find the area of triangle whose base is 24 cm and whose altitude of 1.5dm.​

Answer 1

Given:

↬ Base of Triangle= 24cm

↬ Altitude or height of Triangle= 1.5dm

To Find:

Area of given triangle

Solution:

We know that,

⟼ $\bf{Area\:of\:Triangle=\dfrac{1}{2}\times Base\times Height}$

⟼ 1dm = 10cm

Now,

Height of Triangle= 1.5dm= 1.5×10cm= 15cm

So,

$\sf{Area\:of\:Triangle=\dfrac{1}{\cancel{2}}\times\cancel{24}\times15}$

$\sf{Area\:of\:Triangle=12\times15}$

$\sf\pink{Area\:of\:Triangle=180\:cm^{2} }$

Hence, the area of given triangle is 180 cm².

Answer 2

Answer:

Hence, area of triangle will be 180 Sq. cm

Step-by-step explanation:

In context to question asked,

We have to determine the area of triangle.

As per data given in the question,

We have,

Base of triangle = 24 cm

Height of triangle = 1.5 dm

As here, height is in decimeter. so we will convert it into cm

As we know that,

10 cm = 1 dm

So, 1.5 cm = 15 cm

As we know that,

Triangle is a three sided figure,

Sum of all angles of the triangle is 180 degree.

The area of triangle can be determined by using formula $Area = \frac{1}{2} \times base \times Height$

So, for determining the area of triangle we will put the value of base and height given in the question in above formula,

Thus we will get it as,

$Area =\frac{1}{2} \times 24 \times 15\\=>Area = 12 \times 15\\=>Area =180 \:cm^2$