Question

find the area of triangle whose base is 40cm and corresponding altitude is 8cm​

Answer 1

Area of triangle =    

×b×h  

b=40cm,h=80 cm  

∴A= 1/2 x h x b  

40×8/2 cm  

=1600 cm  

Answer 2

$\huge\cal \underbrace \red{Solution}$

$\sf \purple{\star \: Area \: of \: triangle = \frac{1}{2} \times base \times height}$

$\implies \frac{1}{2} \times 40 \times 8$

$\implies \frac{1}{2} \times 320$

$\implies \: 160 \tt {cm}^{2}$

Hence, area of triangle is $160 \sf{cm}^{2}$