Question

Find the area of triangle whose length is 52, 56 60

Answer 1

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•Find the area of triangle whose length is 52, 56 60

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•1344 cm²

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Half of perimeter (s)

=(52+56+60)/2=84cm

now applying the Herons formula...,

$area = \sqrt{s(s - a)(s - b)(s - c)}$

now..

$area = \sqrt{84(84- 52)(84-56)(84 - 60) } \\ = > area = \sqrt{84 \times 32 \times 28 \times 24} \\ = > area = 1344cm {}^{2}$

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Answer 2

Answer:

1344

Step-by-step explanation:

60² = 56² + 52² - 2.56.52.cos∝

cos∝ = ( 56² + 52² - 60²)/2.56.52 = 2240/2.56.52 = 5/13

sin∝ = 12/13

area = bh sin∝/2 = 56.52.6/13 = 56x24 = 1344