Math, asked by rubaani240, 1 year ago

Find the area of triangle whose point are(3,-1),(-1-2) and (5,6)​

Answers

Answered by azizalasha
1

Answer:

13√10/√17

Step-by-step explanation:

points areA(3,-1),B(-1,-2) and C(5,6)​

equation of AB

y+1/x-3 = -1/-4 = 1/4

4y+4 = x-3 , x-4y-7 = 0

Height of triangle = 5-24-7/√17 = 26/√17

length of AB = √10

area = 13√10/√17

Answered by manyadalela
1

Step-by-step explanation:

area =1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|

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