Find the area of triangle whose point are(3,-1),(-1-2) and (5,6)
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Answered by
1
Answer:
13√10/√17
Step-by-step explanation:
points areA(3,-1),B(-1,-2) and C(5,6)
equation of AB
y+1/x-3 = -1/-4 = 1/4
4y+4 = x-3 , x-4y-7 = 0
Height of triangle = 5-24-7/√17 = 26/√17
length of AB = √10
area = 13√10/√17
Answered by
1
Step-by-step explanation:
area =1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
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