Question

Find the area of triangle whose side is 4cm, 8cm and 12 cm.​

Answer 1

Answer:

8root6

Step-by-step explanation:

through heron's formula

sides= 4, 8, 12

semi perimeter= 12 ( 12+4+8/2 = 24/2 = 12)

= root[ s(s-a)(s-b)(s-c)]

= root[ 12 (12-4) (12-8) (12-12)]

= root(12 * 8 * 4 * 1)

= root(2*2*3*2*2*2*2*2*1)

= 2*2*2root(3*2)

=8root6

Answer 2

Step-by-step explanation:

Given :

a = 4cm

b = 8cm

c = 12cm

Find :

The area of a triangle.

Solution :

$s = \frac{a + b + c}{2}$

$s = \frac{4 + 8 + 12}{2}$

$s = \frac{24}{2}$

$s = 12.$

Area of a triangle

$\sqrt{s(s - a)(s - b)(s - c)}$

$\sqrt{12(12 - 4)(12 - 8)(12 - 12}$

$\sqrt{12 \times 8 \times 4 \times 0}$

$\sqrt{0} \: cm ^{2}$

Hence :

Area of triangle is 0 cm².

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