Find the area of triangle whose sides are 24cm, 32cm and 40cm
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Answer:
Step-by-step explanation:
a = 40 cm
b = 24 cm
c = 32 cm
a + b + c = 40 + 24 +32 = 96
S = a +b + c /2 = 96/2 = 48 cm
S - a = 48 - 40 = 8 cm
S - b = 48 - 24 = 24 cm
S - c = 48 - 32 =16 cm
Area = √S*(S-a) * (S-b) * (S-c)
= √ 48 * 8 * 24 * 16 = √ 6 * 8 * 8 * 6 * 2 * 2 * 4 * 4
= 6 * 8 * 2 * 4 = 384 Sq. cm
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