plzz help me, I'll mark you as brainliest...........
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Construction of ΔABC:
- Draw a line segment AB = 6 cm.
- Pass a ray AX from A such that ∠BAX = 50°.
- With A as vertex and a radius of 8 cm, draw an arc on AX.
- Mark this point on AX as C.
- Join BC.
- ABC is the required triangle.
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thx bro
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